Respostas
respondido por:
10
raiz de 576= 24
Fatorei a raiz de 576
576/2
288/2
144/2 Obs: junto em pares o 2 e o 3
72/2 2*2*2*3= 24
36/2
18/2
9/3
3/3
1
raiz de 14400= 120
Fatorei a raiz de 14400 fazendo o mesmo procedimento
14400/2
7200/2 Obs: junto em pares o 2, o 3 e o 5
3600/2 2*2*2*3*5= 120
1800/2
900/2
450/2
225/3
75/3
25/5
5/5
1
Fatorei a raiz de 576
576/2
288/2
144/2 Obs: junto em pares o 2 e o 3
72/2 2*2*2*3= 24
36/2
18/2
9/3
3/3
1
raiz de 14400= 120
Fatorei a raiz de 14400 fazendo o mesmo procedimento
14400/2
7200/2 Obs: junto em pares o 2, o 3 e o 5
3600/2 2*2*2*3*5= 120
1800/2
900/2
450/2
225/3
75/3
25/5
5/5
1
BiaMarley13:
se quiser coloco os cálculos, só falar
ss
Coloque os cálculos, por gentileza.
Dessa maneira atual, estão apenas os resultados, que não garantem que sua resposta esteja correta.
espero que possam entender, tentei deixar o mais claro possivel
Boa resposta. ^^
respondido por:
11
Olá.
Primeiro, fatoremos ambos os números.
Vamos começar pelo √576
![\Large\begin{array}{llll}576&|&2\\288&|&2\\144&|&2\\72&|&2\\36&|&2\\18&|&2\\9&|&3\\3&|&3\\1&|&=&2^6\cdot3^2\end<br />{array}\\\\\\ \Large\begin{array}{l} \sqrt[2]{2^6\cdot3^2}=\\ 2^3\cdot3=\\ 8\cdot3=\\ \boxed{24} \end{array}](https://tex.z-dn.net/?f=%5CLarge%5Cbegin%7Barray%7D%7Bllll%7D576%26amp%3B%7C%26amp%3B2%5C%5C288%26amp%3B%7C%26amp%3B2%5C%5C144%26amp%3B%7C%26amp%3B2%5C%5C72%26amp%3B%7C%26amp%3B2%5C%5C36%26amp%3B%7C%26amp%3B2%5C%5C18%26amp%3B%7C%26amp%3B2%5C%5C9%26amp%3B%7C%26amp%3B3%5C%5C3%26amp%3B%7C%26amp%3B3%5C%5C1%26amp%3B%7C%26amp%3B%3D%26amp%3B2%5E6%5Ccdot3%5E2%5Cend%3Cbr+%2F%3E%7Barray%7D%5C%5C%5C%5C%5C%5C+%5CLarge%5Cbegin%7Barray%7D%7Bl%7D+%5Csqrt%5B2%5D%7B2%5E6%5Ccdot3%5E2%7D%3D%5C%5C+2%5E3%5Ccdot3%3D%5C%5C+8%5Ccdot3%3D%5C%5C+%5Cboxed%7B24%7D+%5Cend%7Barray%7D+ "\Large\begin{array}{llll}576&|&2\\288&|&2\\144&|&2\\72&|&2\\36&|&2\\18&|&2\\9&|&3\\3&|&3\\1&|&=&2^6\cdot3^2\end<br />{array}\\\\\\ \Large\begin{array}{l} \sqrt[2]{2^6\cdot3^2}=\\ 2^3\cdot3=\\ 8\cdot3=\\ \boxed{24} \end{array}")
Agora, √14.400
![\Large\begin{array}{rrrr} 14400&|&2\\7200&|&2\\3600&|&2\\1800&|&2\\900&|&2\\450&|&2\\225&|&3\\75&|&3\\25&|&5\\5&|&5\\1&|&=&2^6\cdot3^2\cdot5^2 \end{array}\\\\\\ \Large\begin{array}{l} \sqrt[2]{2^6\cdot3^2\cdot5^2}=\\ 2^3\cdot3\cdot5=\\
8\cdot15=\\ \boxed{120} \end{array}\\\\\\](https://tex.z-dn.net/?f=%5CLarge%5Cbegin%7Barray%7D%7Brrrr%7D+14400%26amp%3B%7C%26amp%3B2%5C%5C7200%26amp%3B%7C%26amp%3B2%5C%5C3600%26amp%3B%7C%26amp%3B2%5C%5C1800%26amp%3B%7C%26amp%3B2%5C%5C900%26amp%3B%7C%26amp%3B2%5C%5C450%26amp%3B%7C%26amp%3B2%5C%5C225%26amp%3B%7C%26amp%3B3%5C%5C75%26amp%3B%7C%26amp%3B3%5C%5C25%26amp%3B%7C%26amp%3B5%5C%5C5%26amp%3B%7C%26amp%3B5%5C%5C1%26amp%3B%7C%26amp%3B%3D%26amp%3B2%5E6%5Ccdot3%5E2%5Ccdot5%5E2+%5Cend%7Barray%7D%5C%5C%5C%5C%5C%5C+%5CLarge%5Cbegin%7Barray%7D%7Bl%7D+%5Csqrt%5B2%5D%7B2%5E6%5Ccdot3%5E2%5Ccdot5%5E2%7D%3D%5C%5C+2%5E3%5Ccdot3%5Ccdot5%3D%5C%5C+%0A8%5Ccdot15%3D%5C%5C+%5Cboxed%7B120%7D+%5Cend%7Barray%7D%5C%5C%5C%5C%5C%5C "\Large\begin{array}{rrrr} 14400&|&2\\7200&|&2\\3600&|&2\\1800&|&2\\900&|&2\\450&|&2\\225&|&3\\75&|&3\\25&|&5\\5&|&5\\1&|&=&2^6\cdot3^2\cdot5^2 \end{array}\\\\\\ \Large\begin{array}{l} \sqrt[2]{2^6\cdot3^2\cdot5^2}=\\ 2^3\cdot3\cdot5=\\
8\cdot15=\\ \boxed{120} \end{array}\\\\\\")
Qualquer dúvida, deixe nos comentários.
Bons estudos.
Primeiro, fatoremos ambos os números.
Vamos começar pelo √576
Agora, √14.400
Qualquer dúvida, deixe nos comentários.
Bons estudos.
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