Question

calculando a derivada da função y=[1^365+log2/√19-x]

Answer 1

y = f(x)/g(x)
y' = [f'(x).g(x) - g'(x).f(x)]/[g(x)]²

y = [(1 + log2)/(√19 - x)]
y' = [(1 + log2)'.(√19 - x) - (√19 - x)'.(1 + log2)]/(√19 - x)]²
y' = 0.(√19 - x) - (-1).(1 + log2)]/(√19 - x)²
y' = [(1 + log2)/(√19 - x)²]