Question

x²+x+1=0
x²+x-6=0
(x+2)(x-3)
(x+2)(x+3)

Answer 1

x²+x+1=0
∆= b²-4ac
∆= 1²-4.1.1
∆= 1-4
∆= -3 não pertence aos Reais

x²+x-6=0
∆= b²-4ac
∆= 1²-4.1.(-6)
∆= 1+24
∆= 25

x= -b±√∆/2a
x= -1±√25/2.1
x= -1±5/2

x1= -1+5/2
x1= 4/2
x1= 2

x2= -1-5/2
x2= -6/2
x2= -3

(x+2)(x-3)
x²-3x+2x-6
x²+x-6

(x+2)(x+3)
x²+3x+2x+6
x²+5x+6