Question

considere f(x)= mx+b, f(-2)=3 e (f(4)=1 qual valor de b

Answer 1

$f(x)=mx+b\\f(-2)=3\\-2m+b=3\\f(4)=1\\4m+b=1\\\\ \left \{ {{4m+b=1} \atop {-2m+b=3}} \right. \\6m=-2\\\\m=\frac{-1}{3}\\\\4m+b=1\\b=1-4m\\\boxed{b=1+\frac{4}{3}=\frac{3}{3}+\frac{4}{3}=\boxed{\frac{7}{3}}}$