Question

Alguém pode me ajudar?

Answer 1

a) (x+1)² -> (x+1)(x+1) -> x²+x+x+1 -> x²+2x+1

b) (2x+10)² -> (2x+10)(2x+10) -> 2x²+20x+20x+100 -> 2x²+40x+100

c) (xy+1/3)² -> (xy+1/3)(xy+1/3) -> x²y²+ 1xy/3 + 1xy/3 + 1/9 -> x²y²+ 2xy/3+1/9

d) (x+5)² = (x+5)(x+5) = x² + 5x + 5x + 25 = x² + 2x^8 + 4x^6

e) (x^5 + 2x³)² = (x^5 + 2x³)(x^5 + 2x³) = x^10 + 2x^8 +2x^8 + 4x^6 = x^10 + 4x^8 + 4

f) (6 + x)² = (6 + x) (6 + x) = 36 + 6x + 6x + x² = 36 + 12x + x²

g) (2x + xy) = (2x + xy)(2x +xy) = 4x² + 2x²y + 2x²y + x²y² = 4x² + 4x²y + x²y²

h) (x² +1) = (x² + 1)(x² + 1) = x^4 + x² + x² + 1 = x^4 + 2x² + 1

i) (x + 2y)² = (x + 2y)(x+2y) = x² + 2y + 2y + 4y² = x² + 4y + 4y²

j) (x³ + 1/3)² = (x³ + 1/3)(x³ + 1/3) = x^6 + 1/3x³ + 1/3x³ + 1/9 = x^6 + 1/9x³ + 1/9

Answer 2

a) x²+2x+1

b)4x²+40x+100

c)x²y²+2/3xy+1/9

d)x²+10x +25

e)x¹⁰+4x⁸+4x⁶

f)36+12x+x²

g)4x²+4x²y²+x²+y²

h)x²+2x²+1

i)x²+4xy+4y²

j)x⁶+2x³/3 + 1/9

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