Question

Preparatório militar.

Answer 1

2=10^(0,3)
log2=log10^(0.3)
log2=(0,3).log10.........log2=0.3
segunda parte
5=10^x
log5=log10^x
log5=x.log10
log5=x
log(10/2)=x
log10-log2=x
1-0.3=x
x=0.7