Question

Os divisores naturais de 180

Answer 1

180=2²·3²·5 --> nº divisores= (2+1)·(2+1)·(1+1)= 18 

* Div(180): 

2^0, 2^1, 2^2 --> {1, 2, 4} 
3^0, 3^1, 3^2 --> {1, 3, 9} 
5^0, 5^1 --> {1,5} 

[ {1,2,4}x{1,3,9}] x {1,5} = {1, 3, 9, 2, 6, 18, 4, 12, 36} x {1,5} = 
{1, 3, 9, 2, 6, 18, 4, 12, 36, 5, 15, 45, 10, 30, 90, 20, 60, 180} 

==> Div{180} = {1, 2, 3, 4, 5, 6, 9, 10, 12, 15,18, 20, 30, 36, 45, 60, 90, 180}