Question

como resolver a equaçao x²-11x-42=0

Answer 1

USANDO O BHASKARA Δ=b² -4ac
SENDO A=1   B= -11 C=-42
Δ=( -11) -4×1× -42
Δ=121+168
Δ=289
 
-b+-√Δ/2×a
 x linha = -(-11)+17/2=11+17/2=28/2=14
x 2 linha= -(-11)-17/2=11-17/2= -6/2 = - 3