Question

a)   -(x-2)-2=2 (x - 5)+4x
b)        -2(2x+1) - 3 (x-5)=-8

c)       3 (6x-8) + 10=5(x-2)-(-4+3x)

Answer 1

$a) \\ -(x-2)-2=2 (x - 5)+4x \\ \\ -x + 2 - 2 = 2x - 10 + 4x \\ \\ -x = 6x - 10 \\ \\ -x - 6x = 10 \\ \\ -7x = 10 *(-1) \\ \\ 7x = - 10 \\ \\ x = -\dfrac{10}{7}$

===========================

$-2(2x+1) - 3 (x-5)=-8 \\ \\ \\ 4x + 2 - 9x + 15 = - 8 \\ \\ - 5x + 17 = - 8 \\ \\ -5x = -8 - 17 \\ \\ -5x = -25 *(-1) \\ \\ 5x = 25 \\ \\ x = \dfrac{25}{5} \\ \\ \\ x = 5$

===========================
$3 (6x-8) + 10=5(x-2)-(-4+3x) \\ \\ 18x - 24 + 10 = 5x -10 -3x + 4 \\ \\ 18x - 14 = 2x - 6 \\ \\ 18x - 2x = -6 + 14 \\ \\ 16x = 8 \\ \\ x = \dfrac{8}{16} \\ \\ \\ x = \dfrac{1}{2}$