A fração 2^98 + 4^50 - 8^34 / 2^99 - 32^20 + 2^101 é igual a:? alternativas:a) 1 b ) -11/6 c) 2 d) -5/2e) 7/4
Respostas
respondido por:
17
2^98+4^50-8^34/2^99-32^20+2^101
2^98+2^100-2^102/2^99-2^100+2^101
(2+2^2-2^4)×2^98/(1-2+2^2)×2^99
1+4-16/(1-2+4)×2
-11/3×2
-11/6
Letra b
2^98+2^100-2^102/2^99-2^100+2^101
(2+2^2-2^4)×2^98/(1-2+2^2)×2^99
1+4-16/(1-2+4)×2
-11/3×2
-11/6
Letra b
respondido por:
16
( 2 ) 98 + ( 2 ) 100 - ( 2 ) 102
--------------------------------------
(2 )99 - (2) 100 + ( 2 ) 101
( 2) 98 ( 1 + 4 - 16 )
--------------------------- =
( 2 ) 99 ( 1 - 2 + 4 )
(2 ) 98* (- 11 )
------------------ =
(2) 99* 3
( 2 ) -1 * (- 11 )
------------------- =
3
1 / 2 * ( - 11 )
----------------=
3
1 / 6 * ( - 11 )=
- 11 / 6
alternativa B
--------------------------------------
(2 )99 - (2) 100 + ( 2 ) 101
( 2) 98 ( 1 + 4 - 16 )
--------------------------- =
( 2 ) 99 ( 1 - 2 + 4 )
(2 ) 98* (- 11 )
------------------ =
(2) 99* 3
( 2 ) -1 * (- 11 )
------------------- =
3
1 / 2 * ( - 11 )
----------------=
3
1 / 6 * ( - 11 )=
- 11 / 6
alternativa B
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