Question

$x+10= \frac{8x}{x-2} (x \neq 2)$

Answer 1

$x+10= \frac{8x}{x-2} (x \neq 2) \\ \\ (x + 10)(x-2)=8x \\-------------- \\ x^{2} + 8x - 20 = 8x\\ x^{2} = 20\\ x=+- \sqrt{20} \\ x = -2 \sqrt{5} \\ x"= 2 \sqrt{5}$