• Matéria: Matemática
  • Autor: Brunomoraiis
  • Perguntado 8 anos atrás

{4+2*[32 - 1/4*(2/3 - 1/8)+ 2]+ 16}+1 . Por favor me ajudem

Respostas

respondido por: FibonacciTH
18
A ordem  executar as operações matemáticas:

1º Parêntesis
2º Expoentes
3º Multiplicações e Divisões (da esquerda para a direita)
4º Somas e Subtrações (da esquerda para a direita)
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\mathsf{\left\{4+2\cdot \left[32-\dfrac{1}{4}\cdot \left(\dfrac{2}{3}-\dfrac{1}{8}\right)+2\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[32-\dfrac{1}{4}\cdot \left(\dfrac{2\cdot 8}{3\cdot 8}-\dfrac{1\cdot 3}{8\cdot 3}\right)+2\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[32-\dfrac{1}{4}\cdot \left(\dfrac{16}{24}-\dfrac{3}{24}\right)+2\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[32-\dfrac{1}{4}\cdot \dfrac{16-3}{24}+2\right]+16\right\}+1}
\mathsf{\left\{4+2\cdot \left[32-\dfrac{1}{4}\cdot \dfrac{13}{24}+2\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[32-\dfrac{13}{96}+2\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[34-\dfrac{13}{96}\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[\dfrac{34\cdot 96}{96}-\dfrac{13}{96}\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \left[\dfrac{3264}{96}-\dfrac{13}{96}\right]+16\right\}+1}\\\\\\\mathsf{\left\{4+2\cdot \dfrac{3264-13}{96}+16\right\}+1}
\mathsf{\left\{4+2\cdot \dfrac{3251}{96}+16\right\}+1}\\\\\\\mathsf{\left\{4+\dfrac{2\cdot 3251}{96}+16\right\}+1}\\\\\\\mathsf{\left\{4+\dfrac{3251}{48}+16\right\}+1}\\\\\\\mathsf{20+\dfrac{3251}{48}+1}\\\\\\\mathsf{21+\dfrac{3251}{48}}\\\\\\\mathsf{\dfrac{21\cdot 48}{48}+\dfrac{3251}{48}}\\\\\\\mathsf{\dfrac{1008}{48}+\dfrac{3251}{48}}\\\\\\\mathsf{\dfrac{1008+3251}{48}}\\\\\\\boxed{\boxed{\mathsf{\dfrac{4259}{48}}}}
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