Question

x2-5x-50=0
Alguém sabe resolver?

Answer 1

Olá,

x² - 5x - 50 = 0

a = 1; b = -5; c = -50

Δ = b² - 4ac
Δ = (-5)² - 4 * 1 * (-50)
Δ = 25 + 200
Δ = 225

x' = (-b + √Δ)/2a
x' = (-(-5) + √225)/2
x' = (5 + 15)/2
x' = 20/2
x' = 10

x'' = (5 - 15)/2
x'' = -10/2
x'' = -5

S = {-5, 10}

Bons estudos ;)

Answer 2

Olá, bom dia ☺

Resolução:

x² - 5x - 50 =

Coeficientes:

a= 1, b= -5, c= -50


$\\ \Delta=b^{2}-4.a.c \\ \Delta=(-5)^{2}-4.1.(-50) \\ \Delta=25+200 \\ \Delta=225$

Valores de x:

$\frac{}{}x=\frac{-b\pm \sqrt{\Delta} }{2.a} \\ \\ x=\frac{-(-5)\pm \sqrt{\225} }{2.1} \\ \\ x=\frac{5\pm15}{2} \\ \\x'=\frac{5+15}{2}=\frac{20}{2}=10 \\ \\ x''= \frac{5-15}{2}=\frac{-10}{2}=-5$

$S=\left \{ 10,-5 \right \}$

Bons estudos :)