Question

quais sao as raízes da função f(x)=x^2+3x-4

Answer 1

f(x)= x²+3x-4

$\frac{-3+- \sqrt{(3)^2-4*1*(-4)} }{2*1}= \frac{-3+- \sqrt{25} }{2}= \frac{-3+-5}{2}$

x1= 2/2= 1
x2= -8/2= -4