Question

2000.(1+k)elevado a 10 = 2400

Answer 1

$2000(1+k)^10=2400 \\ \\ (1+k)^{10}=\frac{2400}{2000} \\ \\ (1+k)^{10}=1,2 \\ \\ log(1+k)^{10}=log1,2 \\ \\ 10.log(1+k)=log1,2 \\ \\ log (1+k)=\frac{log1,2}{10} \\ \\ 1+k=10^{\frac{log1,2}{10}} \\ \\ \boxed{k=10^{\frac{log1,2}{10}}-1}$