Question

A equação da reta que passa pelo ponto (3, -2) com inclinação de 60 grau é?

Answer 1

$\mathrm{y=ax+b\ \ \| \ \ (x,y)=(3,-2)\ \ \|\ \ \theta=60\º}\\\\ \mathrm{a=\dfrac{\Delta y}{\Delta x}=\tan{\theta}\ \to\ a=\tan{60\º}=\sqrt{3}}}\\\\ \mathrm{y=x\sqrt{3}+b\ \to\ -2=3\sqrt{3}+b}\\\\ \mathrm{b=-2-3\sqrt{3}\ \to\ b=-(2+3\sqrt{3})}\\\\ \boxed{\mathbf{y=x\sqrt{3}-(2+3\sqrt{3})}}$