• Matéria: Matemática
  • Autor: alissonjrgv
  • Perguntado 8 anos atrás

A derivada de f(x) = [(x+1)/(x+2)]*(3x^2+6x)?

Respostas

respondido por: niltonjr2001
15
\mathrm{f(x)=\bigg(\dfrac{x+1}{x+2}\bigg)(3x^2+6x)\ \to\ f(x)=3x\bigg(\dfrac{x+1}{x+2}\bigg)(x+2)}\\\\ \mathrm{f(x)=3x(x+1)\ \to\ f(x)=3x^2+3x}\\\\ \mathrm{f'(x)=3\frac{d}{dx}(x^2)+3\frac{d}{dx}(x)\ \to\ f'(x)=3.2x+3.1}\\\\ \boxed{\mathbf{f'(x)=6x+3}}
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