Question

Fórmula de bhaskara resolva : (x+3)(x+2)+3(x+3)=0

Answer 1

Bom dia

(x+3)(x+2)+3(x+3)=0
x²+5x+6+3x+9=0
x²+8x+15=0

$\frac{-8+- \sqrt{8^2-4*1*15} }{2*1}= \frac{-8+-2}{2}$

x1= -6/2= -3
x2= -8/2= -4

Answer 2

 (x+3)(x+2)+3(x+3)=0

x² + 2x+3x+6+3x+9 = 0

x² + 8x + 15 = 0

Δ= 8² - 5.1.15 = 64 - 60 = 4

x = -8+/-4
         2.1

x1= - 8+4 = - 2
           2

x2= - 8-4 = - 6
           2