• Matéria: Química
  • Autor: DudaBarbosa2017
  • Perguntado 8 anos atrás

Faça a distributação eletrônica dos seguintes átomos:
6C=
9F=
12MG=
15P=
18AR=
26FE=
35BR=
37RB=
47AG=
53I=
56BA=
68ER=
79AU=
84PO=
87FR=
92U=
100FM=
112CN=
( Me ajudem, por favor! Preciso para amanhã! Grata desde já! ) :)

Respostas

respondido por: anaohara
5
6C= 1s, 2s, 2p(2)
9F= 1s,2s,2p(5)
12Mg= 1s,2s,2p,3s
15P= 1s,2s,2p,3s,3p(3)
18Ar= 1s,2s,2p,3s,3p
26Fe= 1s,2s,2p,3s,3p,4s,3d(6)
35Br= 1s,2s,2p,3s,3p,4s,3d,4p(5)
37Rb= 1s,2s,2p,3s,3p,4s,3d,4p,5s(1)
47Ag= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d(9)
53I= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p(5)
56Ba= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s
68Er= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f(12)
79Au= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d(9)
84Po= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p(4)
87Fr= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s(1)
92U= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f(4)
100Fm= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f(12)
112Cn= 1s,2s,2p,3s,3p,4s,3d,4p,5s,4d,5p,6s,4f,5d,6p,7s,5f

DudaBarbosa2017: Muito obrigada!
Perguntas similares