Question

Determine o conjunto solução de :

a) -(3x-1)-6=3(x-2)+2x

b)(x-4)-(x+3)+3(x-2)-6=0

c)4(3x-2)=-3(x+4)

Answer 1

a) -(3x-1)-6=3(x-2)+2x=>-3x+1-6=3x-6+2x=>5x+3x=-1-6+6=>8x=-1=>x= - 1/8

b)(x-4)-(x+3)+3(x-2)-6=0=>x-4-x-3+3x-6-6=0=> 3x = - 19==> x = -19/3

c)4(3x-2)=-3(x+4) => 12x-8=-3x-12=> 12x+3x= -12+8=> 15x=-4 => x = - 4/15