Question

Determine suas raizes:a) x²-15x+36=0
B)x²-16x+36=0

Answer 1

Olá! ✨

a) x²-15x+36=0

a=1
b= -15
c=36

Δ=(-15)²-4.1.36
Δ=225-144
Δ=81

x'= -(-15)+9 /2
x'=12

x"= -(-15)-9 /2
x"= 6 /2
x"= 3

S={12, 3} <---
_____________________

b) x²-16x-36=0

a=1
b= -16
c= -36

Δ=(-16)²-4.1.(-36)
Δ=256+144
Δ=400

x'= -(-16)+20 /2
x'=36 /2
x'=18

x"= -(-16)-20 /2
x"=16-20 /2
x"= -4 /2
x"= -2

S={-2, 18} <---

Answer 2

Olá,

Questão A)

A= 1
B= -15
C= 36

$X = \frac{-b+ou- \sqrt{ b^{2} -4.a.c} }{2.a}$
$X = \frac{-(-15)+ou- \sqrt{ (-15)^{2} -4.1.36} }{2.1}$
$X = \frac{15+ou- \sqrt{ 225 -4.36} }{2}$
$X = \frac{15+ou- \sqrt{ 225 -4.36} }{2}$
$X = \frac{15+ou- \sqrt{ 225 -144} }{2}$
$X = \frac{15+ou- \sqrt{ 81 } }{2}$
$X = \frac{15+ou-9}{2}$
$X_{1}= \frac{15+9}{2}= \frac{24}{2} = 12$
$X_{2}= \frac{15-9}{2}= \frac{6}{2} = 3$

Questão B)

A = 1
B = -16
C = 36

$X = \frac{-b+ou- \sqrt{ b^{2} -4.a.c} }{2.a}$
$X = \frac{-(-16)+ou- \sqrt{ (-16)^{2} -4.1.36} }{2.1}$
$X = \frac{16+ou- \sqrt{ 256 -4.36} }{2}$
$X = \frac{16+ou- \sqrt{ 256 -144} }{2}$
$X = \frac{16+ou- \sqrt{ 112} }{2}$
$X = \frac{16+ou- \sqrt{ 4^{2}.7 } }{2}$
$X = \frac{16+ou- 4\sqrt{7 } }{2}$

Bom a equação acabaria aqui...
Espero ter ajudado...