Question

8. Seja : → definida pela lei f(x) = 3 . |2x – 1| + 2. Qual é o valor de f(-2) + f(0)?

Answer 1

$f(x) = 3|2x - 1| + 2 \\ \\ \\ f(-2) = 3|2(-2) - 1| + 2\\ \\ f(-2) = 3|-5| + 2 \\ \\ f(-2) = 3(5) + 2 \\ \\ f(-2) = 17 \\ \\ \\ f(0) = 3|2(0) - 1| + 2\\\\f(0) = 3|-1| + 2 \\ \\ f(0) = 3(1) + 2 \\ \\ f(0) = 5 \\ \\ \\ f(-2) + f(0) = 17 + 5\\ f(-2) + f(0) = 22$

Answer 2

Boa tarde Kiko

f(x) = 3 * |2x – 1|  + 2

f(-2) = 3 * l-4 - 1l + 2 = 3*5 + 2 = 17 
f(0) = 3 * l-1l + 2 = 3 + 2 = 5 

f(-2) + f(0) = 17 + 5 = 22