Question

(x+3)²+(x-3)² gostaria de saber apenas o calculo

Answer 1

$(x + 3)^2+(x-3)^2 = (x+3).(x+3)+(x-3).(x-3) \\ \\ x^2+3x+3x+9+x^2-3x-3x+9 \\ \\ x^2+x^2+6x-6x+9+9 \\ \\ 2x^2+18 \\ \\ 2x^2=-18 \\ \\ x^2= \frac{-18}{2} \\ \\ x^2=-9 \\ \\ x= \sqrt{-9} \\ \\ x=3i$

Answer 2

(x + 3)² + (x - 3)²

x² + 6.x + 9 + x² -6.x + 9

2x² + 18

2.(x² + 9)

Espero ter ajudado.