Question

Os valores numéricos das expressões são respectivamente:

a) 4!-2!+0!+1! b) 6!+3!-4!-2!
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2!+3! 5!-4!+4!

a){3,4} b){3,5} c){3,6} d){3,7} e){3,8}

Answer 1

$a ) \frac{4!-2!+0!+1!}{2!+3!} = \frac{4*3*2*1-2*1+1+1}{2*1+3*2*1} = \frac{24-2+2}{2+6} = \frac{24}{8} = \boxed{3} \\ \\ b) \frac{6!+3!-4!-2!}{5!-4!+4} = \frac{6*5*4*3*2*1+3*2*1-4*3*2*1-2*1}{5*4*3*2*1-4*3*2*1+4} = \frac{720+6-24-2}{120-24+4} = \frac{700}{100} =\boxed{ 7}$

Alternativa D)