Question

determinar as raízes complexas da equação y2-2y+2=0.

Answer 1

y+2=0
y=2
y=√2




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Answer 2

$\mathrm{y^2-2y+2=0\ \to\ a=1\ \ \|\ \ b=-2\ \ \|\ \ c=2}\\\\ \mathrm{y=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4.1.2}}{2.1}=}\\\\ \mathrm{=\dfrac{2\pm\sqrt{4-8}}{2}=\dfrac{2\pm\sqrt{-4}}{2}=\dfrac{2\pm2i}{2}=1\pm i}\\\\ \boxed{\boxed{\mathrm{\mathbb{S}=\{y\in\mathbb{C}\ |\ y=1\pm i\}}}}$