Question

(3x^2)^2
(-8×x^4)^2
(2x^5)^3

Me ajudem pfv


2x (x+y)
3x (x-2y)
X^2 (x^3+x^4)
X (4x^2+5)
(12x^2-8x)÷ (2x)
(3y^3+6y^2)÷(3y)

Answer 1

(3x^2)^2
$(3x^{2})^2 = 9x^4$

(-8×x^4)^2
$(-8x^4)^2 = 64x^8$

(2x^5)^3
$(2x^5)^3= 8x^{15}$
≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

2x (x+y) = 2x²+2xy

3x (x-2y) = 3x²-6xy

X^2 (x^3+x^4) = x⁵+x⁶

X (4x^2+5)= 4x³+ 5x

(12x^2-8x)÷ (2x) = 6x-4

(3y^3+6y^2)÷(3y)= y²+2y