Question

Simplifique: Sen 105° + Cos 75°

Answer 1

Bom dia

$sen 105= \frac{ \sqrt{6}+ \sqrt{2} }{4}$
$cos 75= \frac{ \sqrt{6}- \sqrt{2} }{4}$

$\frac{ \sqrt{6}+ \sqrt{2}+ \sqrt{6}- \sqrt{2} }{4}= \frac{ 2\sqrt{6} }{4}$ = √6/2