Question

raiz quadrada de 2 ^3x-1 = raiz cubica de 16^ x-1? gostaria de saber, por favor.

Answer 1

√[2^(3x-1)] = ³√[16^(x-1)]
√[2^(3x-1)] = ³√[(2^4)^(x-1)]
√[2^(3x-1)] = ³√[2^4.(x-1)]
√[2^(3x-1)] = ³√[2^(4x-4)]
2^[(3x-1)/2] = 2^[(4x-4)/3]

Igualando-se os expoentes:

(3x-1)/2 = (4x-4)/3
3.(3x-1) = 2.(4x-4)
9x-3 = 8x-8
9x-8x = -8 + 3
x = -5



Abraços õ/