• Matéria: Matemática
  • Autor: ingnigra
  • Perguntado 8 anos atrás

f(x)=x²+3x-2 determine f(21), f(12), f(-2), f(1), f(4), f(-5), f(6), f(9), f(10)

Respostas

respondido por: emicosonia
0
F(x)=x²+3x-2 determine

 f(21),
f(21) = (21)² + 3(21) - 2
f(21) = 441 + 63 - 2
f(21) = 441 + 61
f(21) = 502

 f(12),
f(12) = (12)² + 3(12) - 2
f(12) = 144 + 36 - 2
F(12) = 144 + 34
F(12) = 178

 f(-2),
f(-2) = (-2)² + 3(-2) - 2
f(-2) = + 4 - 6 - 2
f(-2) = + 4 - 8
f(-2) =- 4

 f(1),
f(1) = (1)² + 3(1) - 2
f(1) = 1 + 3 - 2
f(1) = 4 - 2
f(1) = 2



 f(4),
f(4) = (4)² + 3(4) - 2
f(4) = 16 + 12 - 2
f(4) = 16 + 10
f(4) = 26

 f(-5),
f(-5) = (-5)² + 3(-5) - 2
f(-5) = + 25 - 15 - 2
f(-5) = + 25 - 17
f(-5) = + 8
 
 f(6),
f(6) = (6)² + 3(6) - 2
f(6) = + 36 + 18 - 2
f(6) = 36 + 16
f(6) = 56

 f(9),
f(9) = 9² + 3(9) - 2
f(9) = 81 + 27 - 2
f(9) = 81 + 25
f(9) = 106

 f(10)
f(10) = 10² + 3(10) - 2
f(10) = 100 + 30 - 2
f(10) = 100 + 28
f(10) = 128

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