• Matéria: Matemática
  • Autor: Marentah
  • Perguntado 8 anos atrás

A) 3 sobre √7 - √2
B) 3√2 sobre √5 + √11

Me ajudem ...

Respostas

respondido por: BorgesBR
0
Boa noite! =)

A)

\frac{3}{\sqrt{7}-\sqrt{2}}

\frac{3\sqrt{7-\sqrt{2}}}{\sqrt{7-\sqrt{2}}.\sqrt{7-\sqrt{2}}}

\frac{3\sqrt{7-\sqrt{2}}}{7-\sqrt{2}}

\frac{3\sqrt{7-\sqrt{2}}.(7+\sqrt{2})}{(7-\sqrt{2}).(7+\sqrt{2})}

\frac{3\sqrt{7-\sqrt{2}}.(7+\sqrt{2})}{49-2}

Resposta:

\frac{3\sqrt{7-\sqrt{2}}.(7+\sqrt{2})}{47}

B)

\frac{3\sqrt{2}}{\sqrt{5}+\sqrt{11}}

\frac{3\sqrt{2}.(\sqrt{5}-\sqrt{11})}{5-11}

\frac{3\sqrt{2}.(\sqrt{5}-\sqrt{11})}{-6}

Simplificando:

\frac{\sqrt{2}.(\sqrt{5}-\sqrt{11})}{-2}

\frac{\sqrt{2}\sqrt{5}-\sqrt{2}\sqrt{11}}{-2}

\frac{\sqrt{10}-\sqrt{22}}{-2}

\frac{-(\sqrt{22}-\sqrt{10})}{-2}

Resposta:

\frac{\sqrt{22}-\sqrt{10}}{2}

Espero ter ajudado!
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