Question

Simplifiquem a expressão.

y=1-cos²(3π/2-x)

Obrigado.

Answer 1

y=1-cos²(3π/2-x)

***cos²y+cos²y=1
***sen²y=1-cos³y

y=sen²(3π/2-x)

sen(a-b)=sen(a) *cos(b)-sen(b)*cos(a)
sen(3π/2-x)=sen(3π/2) *cos(x)-sen(x)*cos(3π/2)
sen(3π/2-x)=(-1)*cos(x)-sen(x)*(0)
sen(3π/2-x)=-cos(x)
[sen(3π/2-x)]²=[-cos(x)]²=cos²(x)