Question

URGENTE! POR FAVOR!

Answer 1

4^x-1 -   5  = - 4
             2^1-x

(2^1-x)(4^x-1) -   5  = - 4(2^1-x)  

2^1-x . (2^2)^(x-1) -   5  = - 2^2.(2^1-x)

2^1-x. 2^2x-2 -   5  = - 2^( 2+1 - x )

2^x-1 -   5  = - 2^3 - x 

2^x -   5  = - 2^3 
 2                 2^x

2^x.2^x - 5.2.2^x = - 8

2^2x - 10.2^x + 8 = 0

2^x = a

a^2 - 10a + 8 = 0

Δ = (-10)² - 4.2.8 = 100 - 64 ==> 36


a = 10+/-6
          2

a1 = 8  ; a2 =  2
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2^x = a1  ==> 2^x1 = 8 ==> 2^x1 = 2^3 ==> x1 = 3   

2^x = a2  ==> 2^x2 = 2^1 ==> x2 = 1
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a = 1    e b = 3

1) log(a+b) = 2 ==> log(1+3) = 2 ==> 4 = 2^2   V
        2                           2
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            ___                         ___
2) log(Vb+6) = 1 ==> log(V3+6 ) = 1 ==> V9 = 3^1 ==> 3 = 3   V
        3                           3
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4) log (a.b^2) = - 2 =>(a.b^2)=(1/3)^-2 =>(1.3^2) =(3^-1)^-2 => 3^2 = 3^2  V
        1/3
==========================================================
            ___
8) log √a+1  = - 1/2=>√1+1 = (2.1)^-1/2 ==> √2 = 2^-1/2 => 2^1/2=2^-1/2  F
         2a
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16) log a  = 0 => a = b^0 ==> 1 = 3^0 ==> 1 = 1  V
           b
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verdadeiros são  1,2,4,16 
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