• Matéria: Matemática
  • Autor: Say2sousa
  • Perguntado 8 anos atrás

Simplinfique as expressoes algébricas a seguir,agrupando os termos semelhantes. Em seguida.indentifique o coeficiente e a parte literal de cada um dos termos obtidos.

A)3ab+2ab
B)4,2x+5,3x
C)R/3 +2r

Respostas

respondido por: fabiovofotjjjv
9
a) 3ab + 2ab = 5ab (basta somar)

b) 4,2x + 5,3x = 9,5x (basta somar)

c) r/3 + 2r = r/3 + 6r/3 = 7r/3 (necessário fazer o MMC, transformando o 2r na fração 6r/3 = 2r)

Say2sousa: Obg
Say2sousa: Pf responda esses de novo
Say2sousa: D)5/2y+3/5y - 1/3y
Say2sousa: E)xy+5t-3yx+t
respondido por: dougOcara
4
a) 3ab+2ab = (3+2).ab=5.ab  \\ 
Coeficiente{:}\,\,5 ;\,\,Parte\, literal{:}\,\, ab \\  \\  
b)4,2x+5,3x=(4,2+5,3).x=9,5.x \\ 
Coeficiente{:}\,\,9,5;\,\,Parte\, literal{:}\,\, x \\  \\  
c)\, \frac{R}{3} +2.r= \frac{1}{3} .R+2.r \\ 
c.1)\,Coeficiente{:}\,\,\frac{1}{3};\,\,Parte\, literal{:}\,\, R\\   
c.2)\,Coeficiente{:}\,\,2} ;\,\,Parte\, literal{:}\,\, r\\  \\

d)\, \frac{5}{2}.y+ \frac{3}{5}.y- \frac{1}{3}.y \\  \\   
mmc(2,3,5)=30 \\  \\
 \frac{5}{2}.y+ \frac{3}{5}.y- \frac{1}{3}.y= (\frac{15.5+6.3-1.10}{30}).y =\\   \\ 
=(\frac{75+18-10}{30}).y = \frac{83}{30} .y \\  \\ 
Coeficiente{:}\,\,\frac{83}{30} ;\,\,Parte\, literal{:}\,\, y \\ \\ \\ 
e)\, xy+5.t-3.xy+t \\ 
xy+5.t-3.xy+t=(1-3).xy+(5+1).t=-2.xy+6.t \\ 
e.1)\, Coeficiente{:}\,\,-2;\,\,Parte\, literal{:}\,\, xy \\
e.2)\, Coeficiente{:}\,\,6;\,\,Parte\, literal{:}\,\, t \\
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