Question

me ajudem
a)[40+2x(7-5)]x2-20=
b)45+[(8x5-10:2)+(18:6-2)]=
c)50-2x{7+8:2-[9-3x(5-4)]}=
d)100-3x{5+8:2-[8-3x(3-6]}=

Answer 1

a)[40+2×2]×2-20=
[40+4]x2-20=
44x2-20=
88-20=
68

b)45+[(40-5)+(3-2)]=
45+[35+1]=
45+36=
81

c)50-2×{7+4-[9-3×1]}=
50-2x {7+4-[9-3]}=
50-2×{7+4-6}=
50-2×{11-6}=
50-2×5=
50-10=
40

d) 100-3×{5+4-[8-3×(-3)]}=
100-3×{5+4-[8+9]}
100-3×{5+4-17}=
100-3x{9-17}=
100-3×(-8)=
100+24=
124