Question

como resolver 0,25 ^2x+3 = 4^x-1

Answer 1

$0,25^{2.x+3}=4^{x-1} \\ \\ ( \frac{1}{4} )^{2.x+3}=(2^{2})^{x-1} \\ \\ (2^{-2})^{2.x+3}=2^{2x-2} \\ \\ 2^{-4x-6}=2^{2x-2} \\ \\ -4x-6=2x-2 \\ \\ 2x+4x=2-6 \\ \\ 6x=-4 \\ \\ x=- \frac{4}{6} = - \frac{2}{3}$

Espero ter ajudado.