Question

Qual o valor de x? (Formas na imagem)

Answer 1

A)

$Lado~1:\\\\ 14 - 6 = 8\\\\ Lado~2:\\\\ 12-6 = 6\\\\ Calculo~do~x:\\\\ x^{2} = b^{2} + c^{2} \\ x^{2} = 8^{2} + 6^{2} \\ x^{2} = 64 + 36 \\ x^{2} = 100\\ x = \sqrt{100} \\ x = 10$

B)

Imaginando um linha diagonal MN..

$a^{2} = b^{2} + c^{2} \\ a^{2} = (\sqrt{2})^2 + ( \sqrt{3})^2\\ a^{2} = 2 + 3\\ a^2 = 5\\ a = \sqrt{5}$

Ok, Vamos descobrir o x..

$x^{2} = b^{2} + c^{2} \\ x^{2} = (\sqrt{5})^2 + 1^2\\ x^{2} = 5 + 1\\ x^{2} = 6\\ x = \sqrt{6}$