Question

Como resolver 3x²-15x=0 com formula de bháskara?

Answer 1

Δ = b2 - 4.a.c 
Δ = -152 - 4 . 3 . 0 
Δ = 225 - 4. 3 . 0 
Δ = 225

x = (-b +- √Δ)/2a

x'=[-(-15+√225]/2.3 x''=[-(-15)-√225]/2.3
x'=15+15/6..................x"= 15-15/6
x' = 30 / 6..................x'' = 0 / 6
x' = 5 .........................x'' = 0