Question

resolve essa questão na fórmula de bhaskara 25 t ao quadrado + 10t - 15=0

Answer 1

$\begin{cases}a = 25 \\ b = 10 \\ c = -15\end{cases} \\ \\ \Delta = b^2 - 4.a.c \\ \Delta = 100 + 1500 \\ \Delta = 1600 ~~~~~~ \to \sqrt{\Delta} = 40 \\ \\ \\ x = \dfrac{-b\pm\sqrt{\Delta}}{2a} \\ \\ x = \dfrac{-10 \pm 40}{50} \\ \\ x' = \dfrac{-50}{50} = -1 \\ \\ x'' = \dfrac{30}{50} = \dfrac{3}{5} \\ \\ \\ \boxed{S = \{-1, \frac{3}{5}\}}$