• Matéria: Física
  • Autor: RhafaR
  • Perguntado 9 anos atrás

Passe as temperaturas abaixo para a escala °F

a) 60°C
b) -20°C
c) 100°C
d) -40°C
e) 37°C
f) 0°c

Respostas

respondido por: Juju84
0
a) ( 60/5 ) = ( F-32 ) / 9 
12 = ( F-32) / 9 
108 = F-32
F-32 = 108 
F= 108+32
F= 140°F

b) ( -20/5 ) = ( F -32 ) / 9 
-4 = ( F-32 ) / 9 
-36 = F-32
F-32 = -36
F = -36+32
F = -4°F

c) ( 100/5 ) = ( F-32 ) / 9 
20 = ( F-32 ) / 9 
180 = F-32
F-32 = 180
F = 180+32
F = 212°F

d) ( -40/5 ) = ( F-32 ) / 9
-8 = ( F-32 ) / 9
-72 = F-32
F-32 = -72
F = -72+32
F = -40°F

e) ( 37/5 ) = ( F-32 ) / 9
7,4 = ( F-32 ) / 9
66,6 = F-32
F-32 = 66,6
F = 66,6+32
F= 98°F

f) ( 0/5 ) = ( F-32 ) / 9
0 = ( F-32 ) / 9
0 = F-32
F-32 = 0
F = 0+32
F = 32°F

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