Question

log de 1 na base 3 + log de 5 na base 5 - log de 7 ao quadrado na base 7

Answer 1

$log_31=x \\ 3^x=1 \\ 3^x=3^0 \\ x=0 \\ \\ log_55=y \\ 5^y=5 \\ 5^y=5^1 \\ y=1 \\ \\ log_77^2=z\\7^z=7^2 \\ z=2\\ \\\\\\log_31+log_55-log_77^2 \\ \\ =0+1-2 \\ \\ =-1$