Question

Simplifique a fracão algébrica
2ax+2ay+bx+by/3cx+3cy+dx+dy

Answer 1

(2ax+2ay+bx+by) / (3cx+3cy+dx+dy) = 
[2a*(x+y)+b*(x+y)] / [3c*(x+y)+d*(x+y)] = 
[(2a+b)*(x+y)] / [(3c+d)*(x+y)] =
(2a+b) / (3c+d)