Question

(X+3!+(X+2)!=8(X+1)!

Answer 1

deve ser (X+3)!+(X+2)!=8(X+1)!

(x+3!)+(X+2)!=8(x+1)!

(x+3)(x+2)(x+1)!+(x+2)(x+1)!=8(x+1)!

divida tudo por (x+1)!

(x+3)(x+2)+(x+2)=8

x²+2x+3x+6+x+2=8

x²+6x=0

x(x-6)=0

x=0

ou

x-6=0 ==>x=6

Resposta {0,6}