Question

considerando log2=0,30 e log7=0,85 , resolva: Log49 na base 1/5

Answer 1

log2=0,30 e log7=0,85 , resolva: Log49 na base 1/5

Log 49 = Log49 - log1/5 ==> log7² - (log1 - log5)
     1/5

2log7 - log1 + log5 ==>2log7 - log1 + log10/2 

2log7 - log1 + log10 - log2 ==> 2log7 - 0 + 1 - log2 ==> 2log7 - log2 + 1

2(0,85 ) - 0,30 + 1 ==> 1,70 - 0,30 + 1 ==> 2,40
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log 1 = x ==> 10^x = 1 ==> 10^x = 10^0 ==> x= 0
    10