Question

determinar o mdc e mmc dos polinomios 9x² +18x+9, 15x+15,e 6x²+6

Answer 1

9(x*2 + 2x + 1)  =  9(X + 1)*2   
15(x +1) = 15x + 15
6(x*2 + 1 )

mmc = 9.15.6. (x + 1).(x*2 + 1 )
mmc = 810.(x + 1). (x*2 + 1)
mdc = 1

Answer 2

9x² +18x+9  = 9(x² + 2x + 1) = 9(x + 1 )² = 3.3(x + 1 )(x + 1 )

15x+15 = 15(x+1) = 3.5( x + 1)

6x²+6 = 6(x²+ 1) = 2.3(x² + 1) 

MMC = 2.3.3.5(x + 1 )(x + 1 ) ==> 90(x + 1 )² 

MDC= 3((x+1