• Matéria: Matemática
  • Autor: TataDN
  • Perguntado 8 anos atrás

Quanto é (2x-y)×(2x+y)×(x-y)

Respostas

respondido por: FibonacciTH
1
Dada a propriedade:

\mathsf{\left(a+b\right)\cdot \left(a-b\right)=a^2-b^2}

= = = = =

Logo:

\mathsf{=\left(2x-y\right)\cdot \left(2x+y\right)\cdot \left(x-y\right)}\\\\\mathsf{=\left[\left(2x-y\right)\cdot \:\left(2x+y\right)\right]\cdot \left(x-y\right)}\\\\\mathsf{=\left[\left(2x\right)^2-y^2\right]\cdot \left(x-y\right)}\\\\\mathsf{=\left(4x^2-y^2\right)\cdot \left(x-y\right)}\\\\\mathsf{=\left(4x^2\cdot x\right)-\left(4x^2\cdot y\right)-\left(y^2\cdot x\right)+\left(y^2\cdot y\right)}\\\\\boxed{\mathsf{=4x^3-4x^2y-xy^2+y^3}}\: \: \checkmark
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