Question

x2+4x-45 com formula de bhaskara

Answer 1

Olá!

x²+4x-45= 0
 
Δ= b²-4ac
Δ= 4²-4·1·-45
Δ= 16+180
Δ= 196

x= -b + ou - √Δ / 2a

x1= -4 + √196 / 2·1
x1= -4+14 / 2
x1= 10/2
x1= 5


x2= -4-√196 / 2·1
x2= -4-14 / 2
x2= -18/2
x2= -9

Espero ter ajudado!

Answer 2

x² + 4x - 45 = 0

A= 1

B= 4

C= - 45

∆= b² - 4ac

∆= 4² - 4 • 1 • ( - 45)

∆= 16 + 180

∆= 196

x= - b ± √∆ / 2a

x= - 4 ± √196 / 2 • 1

x'= - 4 + 14/2 = 10/2 = 5

x''= - 4 - 14/2 = - 18/2 = - 9

S= ( 5 , - 9)