Question

determine o 15 termo da progressão (256, 128, 64, ...)

Answer 1

a15 = a1 * q¹⁴
a15 = 256 * (1/2)¹⁴
a15 = 256 * 1/16384
a15 = 256/16384
a15 = 1/64

Answer 2

pg

$\boxed{an=a_1.q^{n-1}}\\\\an=?\\a_1=256\\q=1/2\\n=15\\\\Substituindo\ os\ valores,\ temos:\\\\\\an=256. \dfrac{1}{2} ^{15-1}\\\\\\\\an=256. \dfrac{1}{2}^{14} \\\\\\an=256. \dfrac{1}{16384} \\\\\\\\an= \dfrac{256}{16384}\\\\\\Simplifca\ por\ 256 \\\\\\\\\boxed{\boxed{an= \dfrac{1}{64}} }$


Forte abraço!