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1º achar x 4 BC CD
_______ = _______ =__________
sen 90° sen 45° sen45°
4 BC CD
______ = _________ = _________
1 √2/2 √2/2
BC=4.√2/2 CD=4.√2/2 ou T Pitagora
BC=2√2 CD=2√2 4²=(2√2)²+y²
16=4.2+y²
16-8=y²
y=√8=2√2
ΔABD
4 AB AD
______ =_______ =________
sen90° sen 60° sen30°
4 AB AD
____=_______ =_________
1 √3/2 1/2
AB= 4.√3/2 AD=4.1/2
AB=2√3 AD=2
Perimetro=2√3+2√2+2√2+2=2√3+4√2+2=2.1,73+4.1,41+2=11,1
_______ = _______ =__________
sen 90° sen 45° sen45°
4 BC CD
______ = _________ = _________
1 √2/2 √2/2
BC=4.√2/2 CD=4.√2/2 ou T Pitagora
BC=2√2 CD=2√2 4²=(2√2)²+y²
16=4.2+y²
16-8=y²
y=√8=2√2
ΔABD
4 AB AD
______ =_______ =________
sen90° sen 60° sen30°
4 AB AD
____=_______ =_________
1 √3/2 1/2
AB= 4.√3/2 AD=4.1/2
AB=2√3 AD=2
Perimetro=2√3+2√2+2√2+2=2√3+4√2+2=2.1,73+4.1,41+2=11,1
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