Question

sendo log2 = 0.30 e log 3 = 0.47 então log 6 raiz 2/5? gostaria de saber, por favor.

Answer 1

Boa noite!

$\log 6\sqrt{\dfrac{2}{5}}=\log 6+\log\sqrt{\dfrac{2}{5}}\\\log\left(2\cdot 3\right)+\log\left(\dfrac{2}{5}\right)^{\dfrac{1}{2}}\\\log 2+\log 3+\dfrac{1}{2}\cdot\log\left(\dfrac{2}{5}\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 5\right)\\\log 2+\log 3+\dfrac{1}{2}\cdot\left[\log 2-\log\left(\dfrac{10}{2}\right)\right]\\\log 2+\log 3+\dfrac{1}{2}\cdot\left(\log 2-\log 10+\log 2\right)\\0,30+0,47+0,5\cdot(0,3-1+0,3)=0,57$

Espero ter ajudado!