• Matéria: Matemática
  • Autor: gabrielpro
  • Perguntado 8 anos atrás

1) Calcule : a)2/5+1/8+3/4 b)1/3+7/9-5/6 c)8 •5/4• 2 d)5/7•9/2 e)6/7 •3• 9/5

2) Resolva as expressões : a)6/7•1/3+9/4÷3/2-5/14 b)17/3-3/4÷1/6+3/10÷9/5 c)(1/9+6/15÷3/5)elevado a 3 d)3/4√25/36-(6/5÷12/5+1/4) elevado a 2

3) Calcule as potências :

a) 2 elevado a 5
b)(7/8) elevado a 2
c)(3/5) elevado a 3
d)(4/9) elevado a 2

4) Efetue os cálculos :
obs - √ raiz quadrada

a)√49
b)√81
c)√9/25
d)√81/64
e)√1/36
f)√169/121

A quem responder por favor coloque o MMC urgentemente

Respostas

respondido por: SeVeRiNo73
4
Vamos lá

1)

2/5 + 1/8 + 3/4 preferi por transformar para decimal 0,4+0,125+0,75=0,6=6/10

1/3 + 7/9 - 5/6 = 6+14-15/18= 5/18

8×5/3×2= 80/3

5/7 × 9/2 = 45/14

6/7×9/5×3 = 162/35

2)

a)6/7•1/3+9/4÷3/2-5/14
6/21+3/2-5/14
=10/7

b)17/3-3/4÷1/6+3/10÷9/5
17/3-3/2/3+3/2
17/3-6/2+3/2= 25/6


c)(1/9+6/15÷3/5)elevado a 3
1/9+2/3=(7/9)³=343/729


d)3/4√25/36-(6/5÷12/5+1/4) elevado a 2
3/4×5/6-(1/2+1/4)²
15/24-(3/4)²
15/24-9/16
1/16

3)

2^5=2×2×2×2×2=32

(7/8)²=49/64

(3/5)²=9/25

(4/9)²=16/81

4)

49|7
7|7
1|

√49=√7×7=7

√81 =9

√(9/25) tira a raiz do denominador e numerador portanto 3/5

√(1/36)=1/6

√(169/121)=13/11

gabrielpro: vwl
SeVeRiNo73: tmj
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